How many liters of gas are released when 12.8 g of copper reacts with concentrated sulfuric acid?

Let’s implement the solution:
1. According to the condition of the problem, we compose the equation:
Cu + 2H2SO4 (conc.) = SO2 + CuSO4 + 2H2O – OBP, sulfur dioxide is evolved;
2. Calculation of molar masses:
M (Cu) = 63.5 g / mol;
M (SO2) = 64 g / mol.
3. Determine the amount of the initial substance, if the mass is known:
Y (Cu) = m / M = 12.8 / 63.5 = 0.2 mol;
Y (SO2) = 0.2 mol since the amount of these substances according to the equation is 1 mol.
4. Find the volume of the gaseous product:
V (SO2) = 0.2 * 22.4 = 4.48 liters.
Answer: in the oxidation-reduction process, sulfur oxide is released in a volume of 4.48 liters.