How many liters of H will it take to recover 32 grams of copper oxide?

univerkov | January 17, 2021 | education

Given:
m (CuO) = 32 g
To find:
V (H2)
Decision:
CuO + H2 = H2O + Cu
n (CuO) = m / M = 32 g / 80 g / mol = 0.4 mol
n (CuO): n (H2) = 1: 1
n (H2) = 0.4 mol
V (H2) = n * Vm = 0.4 mol * 22.4 L / mol = 8.96 L
Answer: 8.96 L

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