How many liters of hydrogen are formed by the interaction of 13 g of zinc with an excess of hydrochloric acid hcl.

Zinc metal reacts with hydrochloric (hydrochloric) acid to release hydrogen gas and form zinc chloride. The reaction is described by the following equation:

Zn + 2HCl = ZnCl2 + H2;

1 mole of metal reacts with 2 moles of acid. This synthesizes 1 mol of salt and 1 mol of hydrogen.

Let’s calculate the available chemical amount of zinc.

M Zn = 65 grams / mol;

N Zn = 13/65 = 0.2 mol;

The same amount of hydrogen will be synthesized. Let’s calculate its volume.

To do this, we divide its volume by the volume of 1 mole of ideal gas, which is 22.4 liters.

N H2 = 0.2 mol;

V H2 = 0.2 x 22.4 = 4.48 liters;