How many liters of hydrogen are formed when 6.5 g of zinc react with 7.3 g of hydrochloric acid?

Zinc is a metal that actively dissolves in hydrochloric acid to form a water-soluble salt.

The chemical reaction is described by the following equation:

Zn + 2HCl → ZnCl2 + H2;

In accordance with the coefficients of this equation of hydrogen, an amount equivalent to the chemical amount of dissolved zinc will be released.

Let’s calculate the chemical amount of zinc.

M Zn = 65 grams / mol;

N Zn = 6.5 / 65 = 0.1 mol;

Let’s calculate the molar amount of hydrochloric acid.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 7.3 / 36.5 = 0.2 mol;

0.1 mol of zinc will react with 0.2 mol of acid.

Let us determine the volume of 0.1 mol of hydrogen. To this end, we multiply the chemical amount of gas by the volume of 1 mole of ideal gas filling the volume of 22.4 liters.

V H2 = 22.4 x 0.1 = 2.24 liters;