How many liters of hydrogen are formed when magnesium reacts with 36.6 g

How many liters of hydrogen are formed when magnesium reacts with 36.6 g of hydrochloric acid according to the reaction equation Mg + HCl = MgCl2 + H2?

Magnesium interacts with hydrochloric acid. In this case, magnesium chloride is synthesized and hydrogen gas is released. This reaction is described by the following chemical reaction equation:

Mg + 2HCl = MgCl2 + H2;

In accordance with the coefficients of the equation, in the reaction of 2 mol of acid, 1 mol of hydrogen gas is released.

Let’s calculate the chemical amount of the acid. To do this, divide its weight by the weight of 1 mole of acid.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 36.6 / 36.5 = 1.003 mol;

During the reaction, half the amount of hydrogen will be synthesized.

We calculate its volume, for this we multiply the amount of substance by the volume of 1 mole of gas (22.4 liters):

V H2 = 1.003 / 2 x 22.4 = 11.234 liters;