How many liters of hydrogen are obtained by dissolving 327 grams of zinc in sulfuric acid?

Zinc metal reacts with sulfuric acid to release hydrogen gas and form zinc sulfate. The reaction is described by the following equation:

Zn + H2SO4 = ZnSO4 + H2;

1 mole of metal reacts with 1 mole of acid. This synthesizes 1 mol of salt and 1 mol of hydrogen.

Let’s calculate the amount of zinc.

M Zn = 65 grams / mol;

N Zn = 327/65 = 5.031 mol;

During the reaction, 5.031 mol of hydrogen will be synthesized. Let’s calculate its volume.

To do this, multiply the amount of substance by the volume of 1 mole of gas.

V H2 = 5.031 x 22.4 = 112.7 liters;

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