How many liters of hydrogen are released during the interaction of 28 g iron with 200 g sulfuric acid with a 12% mass fraction of acid.

univerkov | February 17, 2021 | education

1. Let’s find the mass of Н2SO4 in the solution.

W = m (substance): m (solution) × 100%, hence

m (substance) = (m (solution) × W): 100%.

m (substance) = (200 g × 12%): 100% = 24 g.

2.Let’s find the amount of substance Н2SO4.

M (H2SO4) = 98 g / mol.

n = 24 g: 98 g / mol = 0.24 mol.

Fe + H2SO4 = FeSO4 + H2.

M (Fe) = 56 g / mol.

n = 28 g: 32 g / mol = 0.5 mol (excess).

For 1 mol of H2SO4 there is 1 mol of H2.

The substances are in quantitative ratios of 1: 1.

n (H2) = n (H2SO4 H2SO4) = 0.24 mol.

Let’s find the volume of H2.

V = n Vn, where Vn is the molar volume of gas, equal to 22.4 l / mol.

V = 0.24 mol × 22.4 L / mol = 5.376 L.

Answer: 5.376 liters.

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