How many liters of hydrogen can be collected if 10 g of aluminum is dissolved in hydrochloric acid? product yield 90%

To solve, we write down data on the condition of the problem:

m = 10 g X l -? W = 90%

2Al + 6HCl = 2AlCl3 + 3H2 – OBP, hydrogen is evolved;
Let’s make the calculations:
M (Al) = 26.9 g / mol;

M (H2) = 2 g / mol.

Determine the amount of the original substance:
m (Al) = m / M = 10 / 26.9 = 0.37 mol.

Proportion:
0.37 mol (Al) – X mol (H2);

-2 mol -3 mol from here, X mol (H2) = 0.37 * 3/2 = 0.55 mol.

We find the volume of H2, taking into account the product yield:
V (H2) = 0.55 * 22.4 = 12.32 liters (theoretical volume);

V (H2) = 12.32 * 0.90 = 11.08 l (practical volume).

Answer: hydrogen produced with a volume of 11.08 liters