How many liters of hydrogen can be obtained by the action of 13 g of zinc on hydrochloric acid

How many liters of hydrogen can be obtained by the action of 13 g of zinc on hydrochloric acid, which is available in excess? How many grams of salt are formed?

The reaction proceeds according to the following chemical reaction equation:

Zn + 2HCl = ZnCl2 + H2;

Let’s calculate the chemical amount of zinc. For this purpose, we divide its weight by the mass of 1 mole of metal.

N Zn = 13/65 = 0.2 mol;

With this amount of zinc, 0.2 x 2 = 0.4 mol of acid will react. This will synthesize 0.2 mol of hydrogen and 0.2 mol of zinc chloride. Let’s calculate the volume of hydrogen. To do this, multiply the amount of substance by the volume of 1 mole of gas (22.4 liters).

V H2 = 0.2 x 22.4 = 44.8 liters;

Determine the mass of zinc chloride.

M ZnCl2 = 65 + 35.5 x 2 = 136 grams / mol;

m ZnCl2 = 0.2 x 136 = 27.2 grams;