How many liters of hydrogen is required to reduce 1.8 grams of oxide on copper (1).

Monovalent copper oxide is reduced with hydrogen gas when heated. This synthesizes metallic copper and water. The reaction is described by the following chemical reaction equation:

Cu2O + H2 = 2Cu + H2O;

Copper oxide reacts with hydrogen in equal molar amounts.

Determine the chemical amount of monovalent copper oxide.

To do this, divide the weight of the metal by the weight of 1 mole of metal.

M Cu2O = 64 x 2 + 16 = 144 grams / mol;

N Cu2O = 1.8 / 144 = 0.0125 mol;

This reaction requires 0.0125 mol of hydrogen.

M H2 = 2 grams / mol;

m H2 = 2 x 0.0125 = 0.025 grams;

V H2 = 0.0125 x 22.4 = 0.28 liters;