How many liters of hydrogen, measured under normal conditions, would be obtained by reacting 120

How many liters of hydrogen, measured under normal conditions, would be obtained by reacting 120 grams of magnesium with an excess of hydrochloric acid solution?

Metallic magnesium dissolves in hydrochloric acid solution. The chemical reaction proceeds according to the following equation:

Mg + 2HCl = MgCl2 + H2 ↑;

Let’s find the chemical amount of a substance called metallic magnesium.

To do this, we divide this weight by the weight of 1 mole of metallic magnesium.

M Mg = 24 grams / mol;

N Mg = 120/24 = 5 mol;

The same amount of hydrogen gas will be synthesized.

Let’s calculate the volume of hydrogen.

To this end, we multiply the amount of substance by the volume of 1 mole of gas (which is 22.4 liters).

V H2 = 5 x 22.4 = 112 liters;