How many liters of hydrogen will be obtained by the interaction of 29.2 g of hydrochloric acid with zinc.

When dissolved in hydrochloric acid, metallic zinc turns into zinc chloride:

Zn + 2HCl = ZnCl2 + H2;

Let’s calculate the molar amount of hydrochloric acid. To do this, we divide its weight by the mass of 1 mole of the substance.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 29.2 / 36.5 = 0.8 mol;

With this amount of acid, 0.8 / 2 = 0.4 mol of zinc will react. This will synthesize 0.4 mol of hydrogen and 0.4 mol of zinc chloride. Let’s find the volume of hydrogen. To do this, multiply the amount of substance by the volume of 1 mole of gas (which is 22.4 liters).

V H2 = 0.4 x 22.4 = 8.96 liters;