How many liters of hydrogen will be obtained by the interaction of 4 g of calcium with water if the product

How many liters of hydrogen will be obtained by the interaction of 4 g of calcium with water if the product yield is 96% of the theoretical.

Ca + 2H2O = Ca (OH) 2 + H2 – OBP, hydrogen evolved;
Calculations:
M (Ca) = 40 g / mol;
M (H2) = 2 g / mol;
Y (Ca) = m / M = 4/40 = 0.1 mol;
Y (H2) = 0.1 mol since the amount of substances is 1 mol.
Find the volume of H2 taking into account the product yield
V (H2) = 0.1 * 22.4 = 2.24 l (theoretical volume);
V (H2) = 0.96 * 2.24 = 2.15 l (practical volume).
Answer: 2.15 liters of hydrogen was obtained