How many liters of hydrogen will be released during the interaction of zinc with hydrobromic acid weighing 6.4 grams.

When dissolved in hydrobromic acid, metallic zinc is converted to zinc bromide. The reaction is described by the following chemical reaction equation:

Zn + 2HBr = ZnBr2 + H2;

Let’s calculate the chemical amount of hydrogen bromide. To do this, we divide its weight by the mass of 1 mole of gas.

M HBr = 1 + 80 = 81 grams / mol;

N HBr = 6.4 / 81 = 0.079 mol;

With this amount of acid, 0.0395 mol of zinc will react. In this case, 0.0395 mol of hydrogen will be obtained. Let’s find its volume. To do this, multiply the amount of substance by the volume of 1 mole of gas (22.4 liters).

V H2 = 0.0395 x 22.4 = 0.8848 liters;