How many liters of hydrogen will be released when dissolving 540 g of aluminum in hydrochloric acid?

Aluminum reacts violently with hydrochloric acid. At the same time, the salt of aluminum chloride is synthesized and bubbles of hydrogen gas are released. The reaction is described by the following equation.

Al + 3HCl = AlCl3 + 3/2 H2;

Let’s calculate the chemical amount of aluminum. To do this, divide its weight by the weight of 1 mole of the substance.

M Al = 27 grams / mol;

N Al = 540/27 = 20 mol;

This will synthesize the same amount of salt.

The chemical amount of released hydrogen will be: 20 x 3/2 = 30 mol

Let’s define its volume.

For this purpose, we multiply the chemical amount of the substance by the volume of 1 mole of gas (filling the space with a volume of 22.4 liters).

V H2 = 30 x 22.4 = 672 liters;