How many liters of nitric oxide (2) are formed when 3.2 grams of copper are dissolved in nitric acid.

univerkov | January 17, 2021 | education

Given:
m (Cu) = 3.2 g
To find:
V (NO)
Decision:
8HNO3 + 3Cu = 2H2O + 2NO + 3Cu (NO3) 2
n (Cu) = m / M = 3.2 g / 64 g / mol = 0.05 mol
n (Cu): n (NO) = 3: 2
n (NO) = 0.05 mol * 2/3 = 0.03 mol
V (NO) = n * Vm = 0.03 mol * 22.4 L / mol = 0.672 L
Answer: 0.672 L

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