How many liters of oxygen are needed to burn 89.6 liters of hydrogen.

univerkov | December 11, 2020 | education

2H2 + O2 = 2H2O
n (H2) = 89.6 / 22.4 = 4 (mol)
By the coefficients of the equation, we can notice that n (O2) = 2 mol
V (O2) = 22.4 * 2 = 44.8 liters
Answer: V (O2) = 44.8 liters

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