How many liters of oxygen are needed to react with 10 liters of nitrogen?

Let’s execute the solution according to the plan:
1. We compose the reaction equation:
N2 + O2 = 2NO – redox reaction, obtained nitric oxide (2), the reaction is endothermic;
2. Determine the amount of mol of nitrogen according to Avogadro’s law:
1 mol gaseous V-va – 22.4 liters. at n. at.
X mol (N2) -10 l. hence, X mol (N2) = 1 * 10 / 22.4 = 0.45 mol;
3. Let’s make a proportion according to the reaction equation:
0.45 mol (N2) – X mol (O2);
-1 mol -1 mol from here. X mol (O2) = 0.45 * 1/1 = 0.45 mol;
4. Let’s calculate the volume of oxygen according to Avogadro’s law:
V (O2) = 22.4 * 0.45 = 10 liters.
Answer: the volume of oxygen is 10 liters.