How many liters of oxygen is required for the complete combustion of 10 mol CH4?
| September 15, 2021 | education
Reaction equation:
CH4 + 2O2 = CO2 + 2H2O.
The ratio of methane and oxygen is 1: 2, therefore, in order to burn 10 mol of methane, oxygen needs 2 times more, 20 mol.
To find the volume of oxygen, we use the formula: V = 22.4 * v, where 22.4 l / mol is the molar volume of gases, v is the amount of substance in moles.
V = 22.4 * 20 = 448 liters.
Answer: 448 liters of oxygen are needed to burn 10 moles of methane.
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