How many liters of oxygen is required to burn 1 kg of hydrogen sulfide?

2H2S + O2 —-> 2H2O + 2S
n (H2S) = 1000 g / 34 g / mol = 29.4 mol
n (O2) = 29.4 / 2 = 14.7 mol
V (O2) = 14.7 mol * 22.4 L / mol = 329.28 L.



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