How many liters of oxygen is required to burn 6.2 phosphorus.

The reaction for the synthesis of pentavalent phosphorus oxide is described by the following chemical reaction equation:

4P + 5O2 = 2P2O5;

4 phosphorus atoms interact with 5 oxygen molecules. In the course of the reaction, 2 molecules of pentavalent phosphorus oxide are synthesized.

Let’s calculate the chemical amount of a substance contained in phosphorus weighing 6.2 grams.

M P = 31 grams / mol;

N P = 6.2 / 31 = 0.2 mol;

0.2 mol of phosphorus will react with 0.2 x 5/4 = 0.25 mol of oxygen.

Let’s calculate its volume.

To do this, multiply the amount of oxygen by the volume of 1 mole of gas.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V O2 = 0.25 x 22.4 = 5.6 liters;