How many liters of oxygen react with 24 g of magnesium?

Magnesium is oxidized very intensively by oxygen. This oxidation reaction is described by the following equation:

Mg + ½ O2 = MgO;

During oxidation, one oxygen atom is attached to the magnesium atom. In this case, one molecule of magnesium oxide is synthesized.

Let’s determine the molar amount of magnesium.

To do this, divide the available weight of magnesium by the weight of 1 mole of this substance.

M Mg = 24 grams / mol; N Mg = 24/24 = 1 mol;

To burn such an amount of magnesium, 2 times less chemical amount of oxygen is required.

Let’s calculate the volume of oxygen. Multiply the volume of gas by the volume of 1 mole, which is 22.4 liters.

V O2 = 1/2 x 22.4 = 11.2 liters;