How many liters of oxygen react with 40 grams of aluminum?
| April 10, 2021 | education
The reaction of aluminum with oxygen is described by the following equation:
4Al + 3O2 = 2Al2O3;
For 4 moles of aluminum, 3 moles of oxygen must be spent.
The molar mass of aluminum is 27 grams / mol.
The number of moles of a substance in 40 grams of aluminum is 40/27 = 1.4815 mol.
The required amount of oxygen will be 1.4815 x 3/4 = 1.11111 mol.
This amount of gas under normal conditions takes a volume of 1.1111 x 22.4 = 24.8886 liters.
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