Metallic magnesium reacts intensely with oxygen. The reaction is described by the following chemical reaction equation:
Mg + ½ O2 = MgO;
During oxidation, one oxygen atom is attached to the magnesium atom. In this case, one molecule of magnesium oxide is synthesized.
Let’s calculate the molar amount of magnesium.
To do this, divide the available weight of magnesium by the weight of 1 mole of this substance.
M Mg = 24 grams / mol; N Mg = 2.4 / 24 = 0.1 mol;
To oxidize this amount of magnesium, 2 times less chemical amount of oxygen is required.
Let’s find the volume of the gas. Let’s multiply the volume of gas and the volume of 1 mole, equal to 22.4 liters.
V O2 = 0.1 / 2 x 22.4 = 1.12 liters;
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