How many liters of oxygen will it take to completely burn 5.6 liters of methane?

To solve the problem, we write the equation:
СН4 + 2О2 = СО2 + 2Н2О – methane combustion reaction, carbon dioxide and water are released;
M (CH4) = 16 g / mol;
M (O2) = 32 g / mol.
Let’s determine the amount of moles of methane, oxygen:
1 mol of gas at n, y – 22.4 liters;
X mol (CH4) – 5.6 liters from here, X mol (CH4) = 1 * 5.6 / 22.4 = 0.25 mol;
0.25 mol (CH4) – X mol (O2);
– 1 mol – 2 mol from here, X mol (O2) = 0.25 * 2/1 = 0.5 mol.
Let’s calculate the volume of oxygen:
V (O2) = 0.5 * 22.4 = 11.2 liters.
Answer: to carry out the reaction, oxygen with a volume of 11.2 liters is required.