How many liters of oxygen will react with magnesium 2.4g?

Metallic magnesium reacts intensely with oxygen. The oxidation reaction is described by the following equation:

Mg + ½ O2 = MgO;

In this reaction, 1 oxygen atom is added to 1 magnesium atom and 1 molecule of magnesium oxide is synthesized.

Find the chemical (molar) amount of magnesium.

Divide the available weight of magnesium by the weight of 1 mole of this substance.

M Mg = 24 grams / mol; N Mg = 2.4 / 24 = 0.1 mol;

The oxidation of this amount of magnesium requires 2 times less molar amount of oxygen.

Let’s calculate the gas volume. To do this, multiply the volume of oxygen by the volume of 1 mole, which is 22.4 liters.

V O2 = 0.1 / 2 x 22.4 = 1.12 liters;