How many liters of propene can be obtained from 3 liters of propane?

Let’s write down the solution:
1. We compose the reaction equation:
С3Н8 = Н2 + С3Н6 – propane dehydrogenation, propene was released;
2. Determine the amount of moles of propane based on the proportion:
1 mol (C3H8) – 22.4 L;
X mol – 3 liters from here,
X mol (C3H8) = 1 * 3 / 22.4 = 0.13 mol;
2. Determine the number of moles of propene, make up the proportion:
0.13 mol (C3H8) – X mol (C3H6)
-1 mol -1 mol from here,
X mol (C3H6) = 0.13 * 1/1 = 0.13 mol
3. Let’s calculate the volume of propene according to Avogadro’s law:
V (C3H6) = 0.13 * 22.4 = 2.9 l.
Answer: propene was released in a volume of 2.9 liters.