How many liters of SO2 taken under normal conditions must be passed through the HClO3

How many liters of SO2 taken under normal conditions must be passed through the HClO3 solution to reduce 16.9 g of it to HCl?

Given:
m (HClO3) = 16.9 g

To find:
V (SO2) -?

Decision:
1) Write the equation of a chemical reaction:
3SO2 + HClO3 + 3H2O => HCl + 3H2SO4;
2) Calculate the amount of HClO3 substance:
n (HClO3) = m (HClO3) / M (HClO3) = 16.9 / 84.5 = 0.2 mol;
3) Determine the amount of substance SO2 (taking into account the coefficients in the reaction equation):
n (SO2) = n (HClO3) * 3 = 0.2 * 3 = 0.6 mol;
4) Calculate the volume of SO2 (under normal conditions):
V (SO2) = n (SO2) * Vm = 0.6 * 22.4 = 13.44 liters.

Answer: The volume of SO2 is 13.44 liters.