How many MB will be transferred in 2 seconds over a channel with a bandwidth of 100 Mbit / s

To solve this problem, you first need to determine the amount of information that will be transmitted through this channel in 2 seconds.

We multiply the transmission time by the specified speed.

Will be:

2 * 100 = 200 Mbps.

As you know, 1 Mbit contains 1,000,000 bits, so the amount of transmitted information will be:

200 * 100,000 = 200,000,000 bits.

We translate this volume into kilobytes.

Since 1 KB contains 1024 bytes, and 1 byte contains 8 bits, we get:

200000000 / (1024 * 8) = 24402.147 KB.

We translate the amount of information into megabytes.

24402.147 / 1024 = 23.83 MB.

Answer: 23.83 MB.