How many meters of fechral wire with a cross-sectional area of 0.5mm² is required to wind a 480W motor rated for 240V?

Initial data: S (cross-section of fechral wire) = 0.5 mm2; P (motor power) = 480 W; U (voltage for which the electric motor is designed) = 240 V.

Reference values: according to the condition ρ (resistivity of fechral) = 1.3 Ohm * mm2 / m.

We express the required length of the Fechral wire from the equality: U ^ 2 / P = R = ρ * l / S and l = U ^ 2 * S / (P * ρ).

Calculation: l = 240 ^ 2 * 0.5 / (480 * 1.3) = 46.15 m.

Answer: To wind the electric motor, you need 46.15 m of fechral wire.