How many minutes was the electrical circuit turned on if the work of moving electric charges in the direct current

How many minutes was the electrical circuit turned on if the work of moving electric charges in the direct current circuit is 19.67 J? The voltage in this circuit is 0.019 kV, and the current is 1.7 mA.

Initial data: A (perfect work of moving electric charges) = 19.67 J; U (voltage in the DC circuit) = 0.019 kV (19 V); I (current) = 1.7 mA (0.0017 A).

The duration of the switching on of the electric circuit is expressed from the formula: A = U * q = U * I * t, whence t = A / (U * I).

Calculation: t = 19.67 / (19 * 0.0017) = 609 s ≈ 10 min.

Answer: The electrical circuit was turned on for 10 minutes.



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