How many mol of salt was obtained if in the reaction the reducing agent gave 36.12 * 10 ^ 23 electrons (Cl2 + Fe)

We compose the reaction equations for this problem
3Cl2 + 2Fe = 2FeCl3
Fe ° -3e = Fe⁺³ II 2 II – oxidation
Cl₂ ° + 2e = 2Cl⁻¹ II 3 II – reduction
Hence it follows that
Fe ° – reducing agent,
Cl₂ ° – oxidizing agent
1 mol of Fe donates 3 electrons, which means that the amount of mol of the formed FeCl3 is equal to n (FeCl3) = (36.12 × 10 23) / 3 / Na
Na – Avogadro’s number 6.02 × 10 23 mol⁻¹, Substitute and get:
n (FeCl3) = (36.12 × 10 23) / 3 / 6.02 × 10 23 = 2 mol
Answer: 2 mol FeCl3