How many mole is 16.8 nitrogen?

Given:
V (N2) = 16.8 l
m (N2) = 16.8 g

To find:
n1 (N2) -?
n2 (N2) -?

1) n (N2) = V (N2) / Vm = 16.8 / 22.4 = 0.75 mol;
2) M (N2) = Mr (N2) = Ar (N) * N (N) = 14 * 2 = 28 g / mol;
3) n (N2) = m (N2) / M (N2) = 16.8 / 28 = 0.6 mol.

Answer: The amount of substance N2 is 0.75 mol and 0.6 mol.



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