How many molecules are contained in 513mg of sucrose С12Н22О11?
| March 28, 2021 | education
Given:
m (C12H22O11) = 513 mg
Find: N (C12H22O11)
Decision:
N = m * Na / M
N = 513 * 6 * 10 ^ 23/342 = 0.009 * 10 ^ 23
Answer: 0.009 * 10 ^ 23
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