How many molecules are contained in a 500 gram pack of NaHCO3 soda?

univerkov | May 6, 2021 | education

1. Calculate the chemical amount of a portion of sodium bicarbonate:

n (NaHCO3) = m (NaHCO3): M (NaHCO3);

M (NaHCO3) = 23 + 1 + 12 + 3 * 16 = 84 g / mol;

n (NaHCO3) = 500: 84 = 5.9524 mol;

2. find the number of molecules in a pack of soda using Avogadro’s constant:

N (NaHCO3) = n (NaHCO3) * Na = 5.9524 * 6.02 * 10 ^ 23 = 3.58 * 10 ^ 24 molecules.

Answer: 3.58 * 10 ^ 24 molecules.

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