How many molecules are there in 280 grams of nitrogen?

given: m (N2) = 280g
find: n (N2)
decision:
N = n * N (a)
the number N (a) is always = 6 * 10 ^ 23
n = m / M
M (N2) = 2 * 14 = 28 g / mol
means n (N2) = 280g / 28g / mol = 10 mol
n (N2) = 10 mol * 6 * 10 ^ 23 = 6 * 10 ^ 24
answer: n (N) = 6 * 10 ^ 24



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