How many molecules are there in bromine 80 g?

| June 18, 2021 | education

Answer: 3.76 * 10 ^ 21 molecules.
Explanation of the solution to the problem: to solve this problem, you must use the following formula:
N = Na * n, where N is the number of molecules of a given substance, Na is purely Avagadro (the value is constant and equal to: Na = 6.02 * 10 ^ 23 mol ^ -1), n ​​is the amount of substance of the given compound, mol.
The amount of substance is determined by the formula:
n = m / M, where m is the mass of the substance, g; M is the molar mass of the substance, M (Br2) = 160 g / mol (found according to the system of chemical elements of DI Mendeleev).
Substituting the values ​​known from the condition of the problem into the formula, we obtain:
N = Na * n = N = Na * m / M = 6.02 * 10 ^ 23 * 1/160 = 3.76 * 10 ^ 21 molecules.



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