How many molecules does 44.8 liters of carbon dioxide contain?

univerkov | February 14, 2021 | education

Given:
M (CO2) = 44.8L
Find: N (CO2)

Decision:

1 way: n = V / Vm, N = n * Na
1) M (CO2) = 44 g / mol
2) n (CO2) = m / M = V / Vm = 44.8 / 22.4 = 2 mol
3) N (H2O) = n * Na = 2 * 6 * 10 ^ 23 = 12 * 10 ^ 23

Method 2: V / Vm = N / Na => N = V * Na / Vm
N (CO2) = 44.8 * 6 * 10 ^ 23 / 22.4 = 12 * 10 ^ 23

Answer: 12 * 10 ^ 23

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