How many molecules of ammonia NH3 are there in 70 grams of it?

Given:
m (NH3) = 70 g

To find:
N (NH3) -?

1) n (NH3) = m (NH3) / M (NH3) = 70/17 = 4.118 mol;
2) N (NH3) = n (NH3) * NA = 4.118 * 6.02 * 10 ^ 23 = 2.48 * 10 ^ 24.

Answer: The number of NH3 molecules is 2.48 * 10 ^ 24.



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