How many moles and how many grams of calcium carbonate are formed when slaked

How many moles and how many grams of calcium carbonate are formed when slaked lime interacts with 7.84 dm³ of carbon dioxide? Ca (OH) ₂ + CO₂ ⇒ CaCO₃ ↓ + H₂O

Let’s calculate the chemical amount of carbon dioxide. To do this, we divide its volume by the volume of 1 mole of gas, equal to 22.4 liters.

N CO2 = 7.84 / 22.4 = 0.35 mol;

The same amount of calcium carbonate will be synthesized.

Let’s calculate its weight. To do this, multiply the amount of a substance by the weight of 1 mole of this substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

m CaCO3 = 100 x 0.35 = 35 grams;