How many moles are contained in 224 liters of carbon monoxide (IV) CO2.

Given:
V (CO2) = 224 l
Vm = 22.4 l / mol
To find:
n (CO2)
Decision:
n (CO2) = V (CO2) / Vm = 224 l / 22.4 l / mol = 10 mol
Answer: 10 mol is contained in 224 liters of carbon monoxide (IV).



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