How many moles of carbon dioxide and water were released during the combustion of 23 grams of ethanol

Reaction equation: C2H5OH + 3O2 = 2CO2 + 3H2O
Let us find the molar mass of ethanol according to the periodic table: M (C2H5OH) = 12 * 2 + 5 + 16 + 1 = 46 g / mol.
Let’s find the amount of ethanol substance: n = m / M = 23 g / 46 g / mol = 0.5 mol.
According to the reaction, 2 mol of carbon dioxide is formed from 1 mol of ethanol, which means 0.5 / 1 = n (CO2) / 2. n (CO2) = 0.5 * 2 = 1 mol. From 1 mol of ethanol, 3 mol of water is formed, which means 0.5 / 1 = n (H2O) / 3. n (H2O) = 0.5 * 3 = 1.5 mol.
Answer: 1 mole of carbon dioxide, 1.5 mole of water.