How many moles of hydrogen will be released when 0.23 g of sodium interacts with water?

univerkov | March 28, 2021 | education

Let’s write the reaction equation:

2Na + 2H2O = 2NaOH + H2 ↑

Let’s find the amount of sodium substance:

v (Na) = m (Na) / M (Na) = 0.23 / 23 = 0.01 (mol).

According to the reaction equation, 1 mol of H2 is formed per 2 mol of Na, therefore, the released amount of hydrogen is:

v (H2) = v (Na) / 2 = 0.005 (mol) = 5 (mmol).

Answer: 0.005 mol.

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