How many moles of hydrogen will be released when 12 g of magnesium react with a sulfuric acid solution?
| July 4, 2021 | education
The equation for the reaction of magnesium with sulfuric acid:
Mg + H2SO4 = MgSO4 + H2
The amount of Mg substance:
v (Mg) = m (Mg) / M (Mg) = 12/24 = 0.5 (mol).
According to the reaction equation, 1 mol of H2 is released per mole of Mg, therefore the amount of hydrogen is:
v (H2) = v (Mg) = 0.5 (mol).
Answer: 0.5 mol.
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