How many moles of hydrogen will be released when 67.5 g of aluminum react with hydrochloric acid?
March 28, 2021 | education
| Aluminum enters into an active reaction with hydrochloric acid. This forms an aluminum chloride salt and releases hydrogen gas. The interaction is described by the following chemical equation.
Al + 3HCl = AlCl3 + 3/2 H2;
Let’s find the chemical amount of aluminum. To do this, we divide its weight by the molar weight of the substance.
M Al = 27 grams / mol;
N Al = 67.5 / 27 = 2.5 mol;
This will synthesize the same amount of salt.
The chemical amount of released hydrogen will be: 2.5 x 3/2 = 3.75 mol
Let’s calculate its volume.
To this end, we multiply the chemical amount of the substance by the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).
V H2 = 3.75 x 22.4 = 84 liters;
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