How many moles of hydrogen will be released when 67.5 g of aluminum react with hydrochloric acid?

Aluminum enters into an active reaction with hydrochloric acid. This forms an aluminum chloride salt and releases hydrogen gas. The interaction is described by the following chemical equation.

Al + 3HCl = AlCl3 + 3/2 H2;

Let’s find the chemical amount of aluminum. To do this, we divide its weight by the molar weight of the substance.

M Al = 27 grams / mol;

N Al = 67.5 / 27 = 2.5 mol;

This will synthesize the same amount of salt.

The chemical amount of released hydrogen will be: 2.5 x 3/2 = 3.75 mol

Let’s calculate its volume.

To this end, we multiply the chemical amount of the substance by the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).

V H2 = 3.75 x 22.4 = 84 liters;

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