How many moles of oxygen is needed for alumina to burn 54 g?

Let’s compose the reaction equation for the reaction of aluminum with oxygen.

2Al + 3O2 = 2Al2O3.

Next, we calculate the amount of aluminum substance. To do this, you must first determine the molar mass of the substance.

M (Al) = 27 g / mol.

In order to calculate the amount of aluminum substance, you must use the following formula.

n = m / M.

n = 54 g / 27 g / mol = 2 mol.

Further, using the reaction equation, we determine the amount of oxygen.

2 moles of aluminum – x moles of oxygen.

2 moles of aluminum – 3 moles of oxygen.

X = 3 * 2/2 = 3 mol.

When solving the problem, it was found that the volume of oxygen reacted with aluminum is 3 mol.

Answer: the amount of oxygen is 3 mol.