How many moles of oxygen is needed for alumina to burn 54 g?
| May 2, 2021 | education
Determine the amount of substance oxygen
Let’s compose the reaction equation for the reaction of aluminum with oxygen.
2Al + 3O2 = 2Al2O3.
Next, we calculate the amount of aluminum substance. To do this, you must first determine the molar mass of the substance.
M (Al) = 27 g / mol.
In order to calculate the amount of aluminum substance, you must use the following formula.
n = m / M.
n = 54 g / 27 g / mol = 2 mol.
Next, using the reaction equation, we determine the amount of oxygen.
2 moles of aluminum – x moles of oxygen.
2 moles of aluminum – 3 moles of oxygen.
X = 3 * 2/2 = 3 mol.
When solving the problem, it was found that the volume of oxygen reacted with aluminum is 3 mol.
Answer: the amount of oxygen is 3 mol.
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