How many moles of P2O5 are formed when P reacts with 16 g O2?

To solve, we write down the equation of the process:

m = 16 g Y -?

4Р + 5О2 = 2Р2О5 – ОВР, phosphorus oxide is released (5);
We make calculations using the formulas of substances:
M (O2) = 32 g / mol;

M (P2O5) = 141.8 g / mol.

3. Determine the amount of oxidizer:

Y (O2) = m / M = 16/32 = 0.5 mol.

4. Proportion:

0.5 mol (O2) – X mol (P2O5);

-5 mol -2 mol hence, X mol (P2O5) = 0.5 * 2/5 = 0.2 mol.

Answer: Phosphorus oxide was obtained in an amount of 0.2 mol.