How many moles of salt are formed by the interaction of 740 g of calcium hydroxide with hydrochloric acid?

Ca (OH) 2 + 2HCl = CaCl2 + 2H2O – ion exchange, calcium chloride is released;

We make calculations:
M Ca (OH) 2 = 74 g / mol;

M (CaCl2) = 111 g / mol.

Determine the amount of the original substance:
Y Ca (OH) 2 = m / M = 740/74 = 10 mol;

Y (CaCl2) = 10 mol since the amount of substances is 1 mol.

Answer: 10 mol of calcium chloride salt was obtained.