How many moles of slaked lime can be obtained by roasting and subsequent water treatment

How many moles of slaked lime can be obtained by roasting and subsequent water treatment of 1 ton of limestone containing 75% Ca CO3?

To synthesize 1 mol of calcium hydroxide, it is necessary to decompose 1 mol of calcium carbonate. In this case, 1 mol of calcium oxide will be synthesized as an intermediate.
Let’s calculate the available chemical amount of calcium carbonate substance.
To do this, divide the available weight of calcium carbonate by the weight of 1 mole of calcium carbonate.
M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;
N CaCO3 = 1,000,000 x 0.75 / 100 = 7500 mol;
The same amount of slaked lime will be synthesized.
N Ca (OH) 2 = 7,500 mol;